Given cos0=3/4 and angle 0 is in Quadrant I, what is the exact value of sin 0 in simplest form? Simplify all radicals if needed.

sinθ=√7/4

Step-by-step explanation:

Here,

cosθ=3/4

b/h=3/4

b=3 and h=4

Using Pythagoras theorem,

h²=p²+b²

4²=p²+3²

16-9=p²

p=√7

Now,

sinθ=√7/4

a: inscribed angles

step-by-step explanation:

i reviewed this question with a peer and teacher, seems to be correct, me later