What is an equation of the line that passes through the point (–2, 5) and is perpendicular to the line y=12x + 5 ? What is an equation of the line that passes through the point (–2, 5) and is perpendicular to the line y=12x + 5 ?

y = 12x + 5

- 12x + y = 5

gradient 1 = -a/b

= -(-12) / 1

= 12/1

= 12

gradient 2 × 12 = -1

Gradient 2 = -1/12

y - y1 = m (x - x1)

y - 5 = -1/12 ( x - (-2))

multiply all, by 12

12y - 60 = - 1 (x + 2 )

12y - 60 = -x - 2

x + 12y = - 2 + 60

x + 12y = 58

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: