Multiply the polynomials (x + 3) (2x – 4). What is the product in the form ax² + bx + c?

answer:

2x²+2x-12

explanation:

(x + 3) (2x – 4)                           [ open the bracket ]

x(2x) -4(x) +3(2x)+ 3(-4)             [ multiplication ]

2x²-4x+6x-12                             [ simplify ]

2x²+2x-12                                  [ final answer ]

We want to multiply two polynomials of degree 1, and get in that way a polynomial of degree 2.

We will get the polynomial: p(x) = 2 * x² + 2 * x - 12

Step-by-step explanation:

We just want to multiply (x + 3) and (2*x - 4).

So we start by writing:

(x+3) * (2*x-4)

Now we just expand this:

(x+3) * (2*x-4) = 2 *  x² + x * (-4) + 3 * (2 * x) + 3 * (-4)

Now we need to simplify the above expression:

2 * x² + x * (-4) + 3 * (2*x) + 3 * (-4) = 2 * x² + (6 - 4) * x - 12 = 2 * x ² + 2 * x - 12

This is the polynomial we wanted to get:

p (x) = 2 * x² + 2 * x - 12

If you want to learn more, you can read:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

don't give

take it once

try and try and you will not

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