Ivy has 4 blue marbles, 2 red marbles, and 3 green marbles. If Ivy randomly chooses 2 marbles without replacement, what is the probability that both are green? Please help fast

1/12

Step-by-step explanation:

Since these are dependent events, the fractions will vary on the second trial.

First trial 3 green marbles out of a total of 9 marbles. That's a 3/9 chances of the marble being green.

Second trial if you already pulled out a green. 2 green marbles are left with 6 other colors. That makes it a 2/8 odds.

Multiply the fractions and you get 6/72, which simplifies to 1/12.

3/9

Step-by-step explanation:

Simply add up the marbles the total being 9 and the 3 green marbles.  

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p