A triangle has vertices at (−2, −2), (−2, −5), and (−4, −5). The triangle is translated 2 units to the right and rotated 90° clockwise about the origin. What are the coordinates of its image? ( , ), ( , ), ( , ) → ( , ), ( , ), ( , ),

Step-by-step explanation:

translated (shifted) 2 units to the right (positive x direction) creates the points

(-2 + 2, -2) = (0, -2)

(-2 + 2, -5) = (0, -5)

(-4 + 2, -5) = (-2, -5)

and now we rotate these points 90° clockwise around the origin.

that means a positive x turns into a negative y, a negative y into a negative x, a negative x into a positive y, and a positive y into a positive x.

and a 0 just trades places.

therefore,

(0, -2) becomes (-2, 0)

(0, -5) becomes (-5, 0)

(-2, -5) becomes (-5, 2)

so, overall

(-2, -2) becomes (-2, 0)

(-2, -5) becomes (-5, 0)

(-4, -5) becomes (-5, 2)

1.5%

step-by-step explanation:

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.