Peter draws two cards in a row from a deck of 52 cards. If Peter doesn't place the first card back in the deck, what is the probability of drawing 2 red kings from the deck?

S(n)=[50]

Step-by-step explanation:

52-2=50

so the S(n)=50

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9

question:

could we have options?