You invested $18,000 in two accounts paying 7% and 8% annual interest, respectively. If the total interest earned for the year was $1290 how much was invested at each rate?

$15,000 was invested at 7%

$3,000 was invested at 8%

Step-by-step explanation:

Let be the amount of money you spend on the 7% account and be the amount of money you spend on the 8% account. With the information given, you can set up two equations:

Rearrange the first equation and multiply the second equation to get:

Then, substitute for in the second equation to get:

Use the distributive property () to get:

Subtract from both sides and combine like terms to get:

Thus, substitute for in the first original equation to get:

Finally, subtract from both sides to reach:

Our answer is $15,000 was invested at 7% and $3,000 was invested at 8%.

Hope this helps :)

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation: