Please help me find Answers for these Questions.

Step-by-step explanation:

for Q9i

(x-3)(x-7)

let (x-3)= a, (x-7)=b

opening the bracket by multiplying bracket a by bracket b

we have x²-7x-3x+21

x²-10x+21

Q9ii (x+1)(3x+2)=x²+2x+3x+2= x²+5x+2

the two answer can be solved by using this formula x=-b±✓b²-4ac

2a

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x

3

step-by-step explanation: