Kenisha evaluated the power as shown. (Three-halves) cubed = StartFraction 3 times 3 times 3 Over 2 EndFraction = StartFraction 27 Over 2 EndFraction
Did Kenisha correctly evaluate the power? If not, why not?

ci

step-by-step explanation:

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v