assume Kobe variant of the Los Angeles Lakers earned $27.8 million to play 80 games, each lasting 48 minutes. find out; a. how much did Bryant earn per game? b. assuming Bryant played every minute of every game, how much does he earns per minute? c. suppose, averaged over course of the year, Bryant practiced 40 hours for every game and played every minute of every game. including the training time, what was hourly salary?

a.)$347,500

b.)$7,239.58333

c.)$267,307.692

Step-by-step explanation:

a.) Kobe gets paid $27,800,000 to play 80 games

$27,800,000 ÷ 80 = 347,500

b.) for every game 48 min, Kobe gets paid $347,500

$347,500 ÷ 48 (the amount of min) = $7,239.58333

c) there are 80 games, each lasting 48 mins

all games add up to 3,840 mins

meaning all games last to 64 hours

assuming he gets paid $27,800,000

for 80 games we can calculate that he gets paid $434,375 an hour for a game

however, including training time this becomes 104 hours

meaning $27,800,000 ÷ 104 = $267,307.692

sum= when you add is how much the whole amount is

distance= when you use angles and it means how far it goes

step-by-step explanation:

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people