A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid • 72 + 24^3 sq. units
• 96^3 sq. units
• 24 + 72^3 sq. units
• 24 + 96^3 sq. units

choice a

Step-by-step explanation:

first need to find the apothem of hexagon. just take only the hexagon. apothem is the line joining center of hexagon to mid point of any side.

to calculate this, apply Pythagoras theorem. apothem will form right angle at the midpoint of side. and bisects the side of hexagon

2^2+apo^2 = radius of hexagon^2

here hexagon is regular. so radius = side = 4

apo^2 = 12

apo = 2√3

total area = 3ab+3bs

a = apothem = 2√3

b = side = 4

3ab = 24√3

s = slant ht = 6

3bs = 72

total area = 72+24√3

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v