Mathematics, 05.02.2022 17:10, jpsaad00

Suppose you have 76 feet for a regular dog pen the function A= 38x-x^2 where x= width gives you the maximum area what is the maximum area round the nearest tenth as necessary A= width=19ft, area =361ft^2

B= width=38ft, area=760ft^2

C= width=38ft, area =361^2

D= width=19ft, area=1083ft^2

Answers: 2

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Suppose you have 76 feet for a regular dog pen the function A= 38x-x^2 where x= width gives you the maximum area what is the maximum area round the nearest tenth as necessary A= width=19ft, area =361ft^2 B= width=38ft, area=760ft^2 C= width=38ft, area =361^2 D= width=19ft, area=1083ft^2

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Suppose you have 76 feet for a regular dog pen the function A= 38x-x^2 where x= width gives you the maximum area what is the maximum area round the nearest tenth as necessary A= width=19ft, area =361ft^2

B= width=38ft, area=760ft^2

C= width=38ft, area =361^2

D= width=19ft, area=1083ft^2