Two buses leave a station at the same time and travel in opposite directions. One bus travels 18 mi/h faster than the other. If the two buses are 994 miles apart after 7 hours, what is the rate of each bus

The distance each bus travels is given as d=tr where

- d is distance bus travels

- t is a time bus travels

- r is the speed of the bus

:

Distance first bus travels for 4 hours is d1=4r.

Distance other bus travels for 4 hours is d2=4(r+12).

:

The total distance between them is 480 miles and since they go in opposite directions this distance is the sum of distances each bus travels.

:

d1+d2=480

4r+4(r+12)=480

4r+4r+48=480

8r+48=480

8r=432

r=432/8

r=54 mph, this is a speed of the first bus

:

r+12=66 mph, this is the speed of the second bus

Hope this helps you :D

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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