Find the number of sides of a regular polygon whose each exterior angle has a measure of 72°.

Step-by-step explanation:

The sum of the exterior angles of a polygon = 360°

The formula for calculating the size of an exterior angle is:

exterior angle of the polygon = 360 ÷ n

(where n is the number of sides)

Therefore,                            72 = 360 ÷ n

Multiply both sides by n:   72n = 360

Divide both sides by 72:         n = 5

Therefore, a polygon whose exterior angle has a measure of 72° has 5 sides.

hows it hangin lol

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3