Help please.
(There are two questions)

1. 2x4=8

  2x3=6

2. 3x4=12

   3x3=9

Step-by-step explanation:

Hello :)

In this problem, you have to create an equation to figure out the length of each bar. The first bar has two sets of 3 blocks; you can see each set by a color change.

Therefore, this equation would be 2 times 3, since there are 2 sets of 3. This answer equates to 6.

The next one has two bars of four blocks. This means it is 2 times 4, because there are two sets of 4 blocks, and this would constitute as the answer 8.

The second question is a bit tricker. If we look at the first bar, we see that there are 3 blocks per set (noted by color change) and we have 3 of those. If we count all of those up, they have 9 blocks overall. After all, 3 times 3 is nine.

The other problem has 4 blocks a set, and there are three of those. 4 times 3 is 12.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

a. she will receive a refund of $278.

step-by-step explanation: