Which elements in the following set are integers? –8, 3∕4, –0.18, 0, 0.16, 5, –2∕7, 6
Question 17 options:

A)

–8, 5, 6

B)

–8,–0.18, 0, 0.16, 5, 6

C)

–8, 3∕4, 0, 5, –2∕7, 6

D)

–8, 0, 5, 6

B. -8, 0, 16 , 5, 6

Step-by-step explanation:

The integers are the set of positive and negative whole numbers.

is an integer because it is a negative whole number.

is not an integer, it is a rational number.

is not an integer because it cannot simplify to a whole number

is an integer because it is a whole number.

is an integer because it simplifies to a whole number.

is an integer because it is a whole number.

is not an integer, it is a rational number.

is an integer because it is a whole number.

Hopes this helps

Let me know if I'm wrong✌

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.