A rocket was launched and its height, h, in metres, above the ground after time, t, in seconds, is represented by h = 11 + 10t - 2t^2. For how many seconds was
the rocket in the air?
a) about 5.93 s
b) about 7.35 s
c) about 6.64 s
d) about 6.27 s

5\16 x 2\5 = 10/80simplify to 1/80

Volume is length times width times height so
20 times 8 times 30 which is 4,800
surface area is ph (p is perimeter of base), h is height.
so perimeter would be length+length+width+width so 20+20+8+8 which is 56. so multiply 56 times 30 which is 1680. hope this !