Find b in triangle TRG. Please help, I'm not sure how to solve for b.

b=4.9

C. is the correct option.

Step-by-step explanation:

In triangle TGN,

Let <RTG be x

cosx= b/h

or, cosx = 2/a

Again,

In triangle TRG,

cosx = b/h

(for bigger right angled triangle)

cosx = a/(4+2)

cosx = a/6

Now

cosx = 2/a = a/6

or, 2/a = a/6

or, 12 = a²

so, a² = 12

Now,

For TRG,

h² = p²+b²

or, 6² = b² + a²(a²=12)

or, 6² = b² + 12

or, 36 = b² + 12

or, 36 -12 = b²

or, b² = 24

or, b = square root 24

so, b = 4.8989

so, b = 4.9