Pl helppp I’ll give brainiest Find the equation of the line that is perpendicular to y = 2/3x - 5 and passes through
the point C (4,7).

y=-3/2x+13

Step-by-step explanation:

The slope of a perpendicular line is the negative inverse. The negative inverse of 2/3 is −3/2

That means the equation of the perpendicular line is y=−3/2x+a

To find a, you need to input the given values into the perpendicular line equation. When you do that, you get 7=-3/2(4)+a

When you solve for a, you get  a=13.

When you input that into the equation, you get a final equation of y=-3/2+13

Please mark as brainliest ;)

y = -3x/2 + 13

Step-by-step explanation:

to solve such kind of maths, follow this process:

find the slope/gradient:

y = 2/3x - 5

y = 2/3 ( x - 15/2 )

so we found our gradient is 2/3

if perpendicular,  m1 * m2  = -1

                             2/3 * m2 = -1

                             m2 = -3/2    this is our gradient is perpendicular

y - 7 = -3/2 (x - 4 )

y = -3x/2 + 6 + 7

y = -3x/2 + 13

Equation of the line is y = -3x/2 + 13

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)

-1/3(x+1)^5

i’m pretty sure this is correct