Q1a If the linear function of mx - y - m - 1 = 0 does not intersect with the circle function of x^2 + y^2 - 4x - 2y + 1 = 0, find the range values of m.

1. 3

2. 4

3. 1

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-wfz

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8