The sum of 4 consecutive odd numbers is 56. find the greatest of the 4 . Explain your answer and please help ASAP

17

Step-by-step explanation:

let the 4 consecutive odd numbers be n , n + 2 , n + 4 , n + 6 , then

n + n + 2 + n + 4 + n + 6 = 56 , that is

4n + 12 = 56 ( subtract 12 from both sides )

4n = 44 ( divide both sides by 4 )

n = 11

n + 2 = 11 + 2 = 13

n + 4 = 11 + 4 = 15

n + 6 = 11 + 6 = 17

The 4 consecutive odd numbers are 11 , 13 , 15 , 17

with the greatest being 17

Let the number be x,

then the consecutive numbers shall be x + 2, x + 4, x + 6

x + x + 2 + x + 4 + x + 6 = 56

4x = 56 - 12

4x = 44

x = 11

other consecutive numbers are = 11 + 2, 11 + 4, 11 + 6

                                                     = 13, 15, 17

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x