1: Evaluate x•y+9•X-3 when x=7 and y=10 2:
2:Evaluate 140=(x+9)+(x+4)2 when x=1 (show steps)

1. 130

2. 0=120

Step-by-step explanation:

1. 7*10+9*7-3

pemdas

70+63-3

130

2. kind of hard to explain but this is what i got

(1+9) + (1+4)*2 = 140

pemdas

10+5*2=140

10+10= 140

20=140

you could subtract at this point...?

140-20=120

0=120

not much context but this is what i got

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.