A football is kicked up from ground level at an initial upward velocity of 80 ft./s. The equation h=-16t^2 + 80t give the height h of the football after t seconds. What are realistic values for t?

Step-by-step explanation:

Note that the given height equation, which is a quadratic) has a graph that opens downward.  Borrowing the quadratic formula, we find the roots of this equation, that is, the t values at which h(t) = 0:

The coefficients of this equation are a = -16, b = 80 and c = 0.

We need to find the roots of this quadratic.  By the quadratic formula,

      -(80) ±√(80² - 4(-16)(0) )         -80 ± 0

t = = = -5/2 and -5/2 (seconds).

                 2(-16)                               -32

The initial height is 0 at t = 0 seconds and the final height 0 at 5/2 seconds.

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)