A horse drags a harrow of mass 50 kg across a field by a rope at a constant speed. f inhe rope is kept horizontal, what is the coefficient of friction if the force of the horen
the rope is 350 N.

0.6

Explanation:

There are four forces on the box:

Weight force mg pulling down,

Normal force N pushing up,

Tension force T pulling 30° above the horizontal,

and friction force Nμ pushing to the left.

Sum of the forces in the y direction:

∑F = ma

N + T sin 30° − mg = 0

N = mg − T sin 30°

Sum of forces in the x direction:

∑F = ma

T cos 30° − Nμ = 0

Nμ = T cos 30°

μ = T cos 30° / N

μ = T cos 30° / (mg − T sin 30°)

Plug in values:

μ = (250 N) cos 30° / ((50 kg) (9.8 m/s²) − (250 N) sin 30°)

μ = 0.59

Rounded to one significant figure, the coefficient of friction is 0.6.

its 50 miles away from the starting point

it would be 0.18 because when the other choices are converted they equal those two numbers.   hope this !