20 pts Help me please

4s + 10p <= 100

p >= 5

Step-by-step explanation:

So it's important to remember here that this isn't one linear inequality to represent everything, it's a system. One of the inequalities that are part of the answer won't answer the entire question by itself, so don't worry about that. It might sound like tedious work, but you can break it down pretty easily into logic.

So the soil costs Marsha $4 per bag, and the plants cost her $10 each. She can't spend more than $100 dollars.

Let p = number of plants and let s = number of bags of soil

If each soil bag costs her $4, then 4s is the amount she spends on soil (4 [which is the cost of each individual soil bag] x number of bags = total cost of soil bags).

If each plant costs her $10, then 10p is the amount she spends on plants (same logic).

Because she can't spend more than $100 on both soil and plants together,

4s + 10p has to be less than or equal to 100.

4s + 10p <= 100

Since she wants to buy at least 5 plants, p has to be greater than or equal to 5.

p >= 5

And there you have it! Your system of inequalities is:

4s + 10p <= 100

p >= 5

Pretty simple c:

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )