Which of the following is an equivalent form of the compound inequality −44 > −2x − 8 ≥ −48? −2x − 8 > −44 and −2x − 8 ≥ −48
−2x > −44 and −8 ≥ −48
−2x − 8 < −44 and −2x − 8 ≤ −48
−2x − 8 < −44 and −2x − 8 ≥ −48

The answer is −2x − 8 < −44 and −2x − 8 ≥ −48. OR answer choice D

Step-by-step explanation:

Step-by-step explanation:

Given compound inequality:

Just split the inequality into two simpler inequalities:

Correct choice is D

ddsf

step-by-step explanation:

dfs

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.