Customer return and refund On December 28, 20Y3, Silverman Enterprises sold $18,000 of merchandise to Beasley Co. with terms 2/10, n/30. The cost of the goods sold was $11,600. On December 31, 20Y3, Silverman prepared its adjusting entries, yearly financial statements, and closing entries. On January 3, 20Y4, Silverman Enterprises issued Beasley Co. a credit memo for returned merchandise. The invoice amount of the returned merchandise was $4,000 and the merchandise originally cost Silverman Enterprises $2,400.

a. Journalize the entries by Silverman Enterprises to record the December 28, 20Y3 sale, using the net method under a perpetual inventory system. If an amount box does not require an entry, leave it blank.

b. Journalize the entries by Silverman Enterprises to record the merchandise returned by Beasley Co. on January 3, 20Y4. If an amount box does not require an entry, leave it blank.

c. Journalize the entry to record the receipt of the amount due by Beasley Co. on January 7, 20Y4. If an amount box does not require an entry, leave it blank.

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

fd

step-by-step explanation: