Solve the simultaneous equation 3x=y+1 y=3+x

x = 1 , y = 4

Step-by-step explanation:

3x = y + 1

=> y + 1 = 3x

=> y = 3x - 1

y = 3 + x

Substituting y = 3x + 1 in y = 3 + x,

=> 3x + 1 = 3 + x

=> 3x - x = 3 - 1

=> 2x = 2

=> x = 2/2

=> x = 1

y = 3 + x

Substituting x = 1,

=> y = 3 + 1

=> y = 4

x=2

y=5

Step-by-step explanation:

y=3x

replace it in 3x=y+1

so"

3x= 3+x+1

3x-x=4

2x=4

x=2

so now we replace x=2 in y=3+x

which gives:

y=3+2

y=5

d

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180