![\textit{area of a rectangle}\\\\ A=Lw~~ \begin{cases} L=length\\ w=width\\[-0.5em] \hrulefill\\ L=\sqrt{125}\\ \qquad \sqrt{5^2\cdot 5}\\ \qquad 5\sqrt{5}\\ w=3\sqrt{5}-4\sqrt{12}\\ \qquad 3\sqrt{5}-4\sqrt{2^2\cdot 3}\\ \qquad 3\sqrt{5}-8\sqrt{3} \end{cases}\implies \begin{array}{llll} A=(5\sqrt{5})(3\sqrt{5}-8\sqrt{3})\\\\ A=15(\sqrt{5})^2-40\sqrt{3}\cdot \sqrt{5}\\\\ A=15\sqrt{5^2}-40\sqrt{3\cdot 5}\\\\ A=15\cdot 5-40\sqrt{15}\\\\ A=75-40\sqrt{15} \end{array}](/tpl/images/2618/0987/53c9c.png)
What is the area of a rectangle that measures 3V5 - 4V12 by V125? PLEASE HELPPP
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Mathematics, 13.01.2022 19:20, HTTYD
What is the area of a rectangle that measures 3V5 - 4V12 by V125? PLEASE HELPPP
Answers: 1
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