The function h is defined as follows. h(x) = 5x²+4
If the graph of h is translated vertically downward by 6 units, it becomes the graph of a function f.
Find the expression for f (x).

The equation you are given is a quadratic. The standard form of a quadratic is y = a(x-h)2 + k where (h,k) is the vertex of the graph, which is a parabola. Vertically moving the graph 4 units upward means that you are moving k +4 units.

y = a(x-h)2 + k            standard form

y = 5x2 - 4                  original equation

y = 5(x-0)2 - 4            re-written in standard form

h = 0     k = -4

Four (4) units up is k + 4--->-4 + 4 = 0.

Therefore, f(x) = 5x2 + 0--->f(x) = 5x2.

Step-by-step explanation:

hope this helps

plz mark brainliest

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)