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Length of smaller square: 4

Length of larger square √32 or 5.66

Area of smaller square: 16

Area of larger square: 32

Step-by-step explanation:

See attachment

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

So for triangle ABD, the length from (-2,2) to (2,2) equals of 1/2 of AD: 8/2 = 4

so the areas of smaller square is 4 x 4 = 16

And for triangle ABD, AD^2 = AB^2 + BD^2

since AB = BD => AD^2 = 2AB^2

AB^2 = (AD^2)/2 = (8^2)/2 = 64/2 = 32

AB = √32

so the area of larger square = (√32)(√32) = 32

Hope this helps

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step-by-step explanation: