A line passes through the point (1, -5) and has a slope of 8. Write an equation in slope-intercept form for this line.

y= -8x+3

Step-by-step-explanation

First you need to plug in your point into m= y^2-y^1/x^2-x^1

When you do that you’ll get 8= y-(-5)/x-(1)
Which would equal 8=y+5/x-1

Then you want to multiply the denominator out of the right side so you would get -8•(x-1)=y+5
Which would equal -8x+8=y+5

Then you subtract 5 from both sides to cancel it out from the right side so y can be by itself
You would get -8x+3=y which is in standard form
We want the slope-intercept form so you move the -8x+3 to the right side and y to the left which would be -y=8x-3 but your y can’t be negative so you divide both sides by -1 then you would get y=-8x+3

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