Robert takes a roast out of the oven when the internal temperature of the roast is 165°F. After 15 minutes, the temperature of the roast drops to 135°F. The temperature of the room is 70°F.

How long does it take for the temperature of the roast to drop to 110°F?

Step-by-step explanation:

Rate of drop of temperature = Change in temperature/Rate

=> (165 - 135)/15

=> 30/15

=> 2 ⁰F/min

Now, The time at which the temperature of will be 70⁰F = 70/Rate

=> 70/2

=> 35 min

Time for 110⁰ F

=> 110/2

=> 55 min

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.