Help please :)) The solutions to a polynomial equation include x = 3 (double root), and x = 2-3i, and has a leading coefficient of (-5). Write the polynomial equation, of smallest degree, with these characteristics, in standard form.

Step-by-step explanation:

Complex roots come in conjugates.  Your roots are

x = -3i

x= 3i

x = 2

x = -i

x = i

Since  i=√-1 , then i2=-1

For the root   x = 3i , we can say that the factor is  

(x - 3i)(x + 3i) = x2 - 9i2

                      = x2 - 9(-1)

                      = x2 + 9

(x - i)(x + i) = x2 - i2

                  = x2 + 1

Then your polynomial is

f(x) = (x - 2)(x2 + 1)(x2 + 9)

Step-by-step explanation:

The roots are:

The polynomial is:

me

step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!