A pole vaulter rested a 17 foot pole against a wall. If the top of the pole hit the wall 14 feet above the ground, how far from the wall is the bottom of the pole

a = √93

a ≈ 9.64

Step-by-step explanation:

We can use the Pythagorean theorem for this: a² + b² = c²

c is given as the hypotenuse, which is the pole with a length of 17 ft

c² is 17²

b is a leg with a height of 14 ft

b² = 14²

We need to find the base leg, a,  distance from the wall to the base of the pole.

Solve:

a² + 14² = 17²

a² + 196 = 289

a² = 93

a = √93

-Chetan K

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.