Find the equation of the tangent line of y = 3x2 at x =2.

Step-by-step explanation:

I will ASSUME you mean y = 3x² at x = 2

The derivative of an equation is the slope the curve at any given point

y' = 6x

so our line slope at x = 2 is 6(2) = 12

at x = 2, y = 3(2²) = 12

so (2, 12) is a point on the line (the point of tangency)

plugging into our slope equation

y = 12x + b

12 = 12(2) + b

b = -12

So the equation of the line tangent to y = 3x² at x = 2 is

y = 12x - 12