What 2 numbers make a product of 160 and sum of 12

first number is 20 Second number I -8

Step-by-step explanation:

Given \: sum \: of \: two \: numbers = 12Givensumoftwonumbers=12

Let \: One \: number = xLetOnenumber=x

Second \: number = ( 12 - x )Secondnumber=(12−x)

\blue { Product \: of \: two \: numbers = -160}Productoftwonumbers=−160

\implies x( 12 - x ) = -160⟹x(12−x)=−160

\implies 12x - x^{2} + 160 = 0⟹12x−x2+160=0

/* Multiplying bothsides by (-1) , we get */

\implies -12x + x^{2} - 160 = 0⟹−12x+x2−160=0

\implies x^{2} - 12x - 160 = 0⟹x2−12x−160=0

/* Splitting the middle term,we get */

\implies x^{2} + 8x - 20x - 160 = 0⟹x2+8x−20x−160=0

\implies x( x + 8 ) - 20( x + 8 ) = 0⟹x(x+8)−20(x+8)=0

\implies ( x + 8 )( x - 20 ) = 0⟹(x+8)(x−20)=0

\implies x + 8 = 0 \: Or \: x - 20 = 0⟹x+8=0Orx−20=0

\implies x = -8 \: Or \: x = 20⟹x=−8Orx=20

\begin{gathered} i ) If \: x = -8 \: then \\text{\O}ne \: number = -8 \end{gathered}i)Ifx=−8thentext\Onenumber=−8

\begin{gathered} Second \: number = 12 - x \\= 12 - (-8) \\= 12 + 8 \\= 20 \end{gathered}Secondnumber=12−x=12−(−8)=12+8=20

\begin{gathered} ii ) If \: x = 20 \: then \\text{\O}ne \: number = 20 \end{gathered}ii)Ifx=20thentext\Onenumber=20

\begin{gathered} Second \: number = 12 - 20 \\= -8 \end{gathered}Secondnumber=12−20=−8

Therefore.,

\begin{gathered} \red{ Required \: two \: numbers \: are } \\\green { -8 \: and \: 12 } \end{gathered}Requiredtwonumbersare−8and12

not possible, no products of 160 and to the sum of 12

Step-by-step explanation:

160, 1

80, 2

40, 4

32, 5

20, 8

16, 10

answer: yard ramps with a level off platform are typically 36 feet long. truck, rather than at an angle, enabling access to those pallets at the very back of the truck. if you are using your yard ramp to convert a loading dock into a drive-in door, we even at 60 inches (5 feet) high and a 30 foot ramp, the slope of the ramp will be less

step-by-step explanation: