Information: Valerie is comparing the cost of block and shredded cheeses. The cost of 8 ounces of shredded cheese is $3.00. Part A: The cost of block cheese is shown in the graph. (see image) Graph the cost of shredded cheese on the graph below.

Part B: What is the equation of the line representing the cost of the shredded cheese?

Part C: Valerie purchases 16 ounces of the less expensive cheese How much does the cheese cost?

So basically to sum this all up i need you to tell me where the dots need to go on the graph for part a, what the equation is for part b, and how much the cheese cost for part c.

THANK YOU

A) See explanation

B)

C) $6

Step-by-step explanation:

Part A: because 8 oz of shredded cheese is $3, 1 oz of shredded cheese is $0.375, and so 3 oz of shredded cheese will be $1.125 (so on the y-axis on the graph), 6 oz will be $2.25 ( on the y-axis), and oz will be $.

Part B: the equation for a line is where m is the gradient of the slope (change in y over change in x) and b is the y-axis intercept. So the equation for this line is .

Part C: Since block cheese costs $1 for 3 oz and shredded cheese costs $1.125, shredded is more expensive. 16 ounces of that will be dollars exactly.

Step-by-step explanation:

Part B: The cost of 8 ounces of shredded cheese is $3.00 ⇒ The cost of 1 ounce of shredded cheese is $0.375

y = 0.375 x

Part C: The cost of 20 ounces of block cheese is $6.00 ⇒ The cost of 1 ounce of block cheese is $0.3

16 oz × $0.3 = $4.80

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.