MATHSWATCH FUNCTIONS QUESTION CAN SOMEONE PLEASE HELP ME!!

Step-by-step explanation:

I'll use y instead of f(x):

The inverse of y [f(x)] = 3 - 5 is

x = 3 - 5

Rearrange to isolate y:

= (x+5)/3

For f(43) we get:

= (43+5)/3

= (48)/3

= 16

y = 4

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Since g(x) = x+1 and h(x)= x^2,

h(g(x)) = (x+1)^2

(x+1)^2

x^2 + 2x + 1

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This is set equal to 3x^2 + x - 5 and we can then solve for x:

3x^2 + x - 5 = x^2 + 2x + 1

2x^2 -x -6 = 0

(x-2)(2x+3) = 0

The solutions are:

x = -3/2 and x = 2

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.