Can anyone please find x

X=25°

Step-by-step explanation:

To solve this problem there are several paths including the use of rules of opposite triangles or then slightly more complex central theorems. We propose a very simple method.

Since the COD angle, the value of which is known because it is equal to 130°, by drawing a line joining point B and point D, we obtain another angle equal to its half. So the CBD angle thus formed is equal to 130/2=65°.

At the same time, we form an ABD triangle with a 90° right in B. We then just need to subtract the first angle found, that is, the 65° CBD angle, to obtain the value of agle x.

90-65=25°.

X=25°

How to prove the theorem of central angle?

Prove Central Angle Theorem. To prove: ∠AOB = 2∠ACB. Proof: Let ∠AOB be the central angle, and ∠ACB the inscribed angle of the circle. Since lines OC, OA, and OB are the radius of the circle and are of the same length, Hence, COA and COB are both isosceles triangles. Let, ∠ACO = α 1 and ∠BCO = α 2.

answer is x<

step-by-step explanation:

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