Really need help with this

Step-by-step explanation:

You have 2 sides given in a right triangle. You can make an equation that will solve for x. In fact the tangent will do. There's no need to solve for the third side.

Tan(x) = opposite / adjacent

opposite = 39

adjacent = 76

Tan(x) = 39/76

Tan(x) = 0.5132

When finding an angle, you need to use the inverse tan.

x = tan-1(0.5132)    Use 2nd function tan(x)

x = 27.16 degrees.

Step-by-step explanation:

first we need the length of the Hypotenuse (UW).

Pythagoras :

c² = a² + b²

with c being the Hypotenuse (the side opposite of the 90 degree angle).

UW² = 76² + 39² = 5,776 + 1,521 = 7,297

UW = sqrt(7297) = 85.42247948...

now we get x from the law of sine :

sinA/a = sinB/b = sinC/c

with the angles always being opposite of the sides.

so, we have

sin(x)/39 = sin(90)/sqrt(7297) = 1/sqrt(7297)

sin(x) = 39/sqrt(7297) = 0.456554296...

x = 27.16498506...° ≈ 27.2°

we could have done it without the Hypotenuse first.

as the angle W is 90-x

sin(x)/39 = sin(90-x)/76 = cos(x)/76

sin(x)/cos(x) = 39/76 = tan(x) = 0.513157895...

x = 27.16498506...° ≈ 27.2°

as expected, it is precisely the same result.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)