The brother is 5 years older than Sister. Find the sum of siblings's ages if their ages 4 years ago were the same as 3: 2.

the sum of siblings' ages is 25 years

Solution given:

let the age of brother be x and sister age be y.

By question at the present age of the brother is 5 years older than his sister. in the equation,

it can be  written as:

x=y+5[1]

again;

Before 4 years

sister's age will be y-4.

brother's age will be y-4+5=y+1

Since their ages 4 years ago were the same as 3: 2.

so according to the question.

3(y-4)=2(y+1)

solving the equation, we get

3y-12=2y=2

3y-2y=2+12

y=14

Before 4 years ago the age of sister is y=14-4=10 years

and the present age of brother is x=y+5=10+5=15 years

now

the sum of siblings' ages=x+y=10+15=25 years

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

360/29

step-by-step explanation: