The base of a triangle is v245 cm and its height is V20 cm. Find its area.

Step-by-step explanation:

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The altitude of a triangle is 6 cm greater than its base. If its area is 108 cm

2

. Find its base and height.

Hard

Solution

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Let the base of the triangle be x.

It is given that the altitude of the triangle is 6 cm greater than its base, therefore, the altitude of the triangle is (x+6).

It is also given that the area of the triangle is 108 cm

2

.

We know that the area of the triangle is A=

2

1

×b×a, therefore,

108=

2

1

(x)(x+6)

⇒x

2

+6x=108×2

⇒x

2

+6x=216

⇒x

2

+6x−216=0

⇒x

2

+18x−12x−216=0

⇒x(x+18)−12(x+18)=0

⇒(x−12)=0,(x+18)=0

⇒x=12,x=−18

Since the length of the triangle cannot be negative thus, x=12.

Hence, the base of the triangle is 12 cm

2450

Step-by-step explanation:

→ List the formula for a triangle

Area = 0.5 × Base × Height

→ Substitute in the numbers

0.5 × 245 × 20

→ Simplify

2450

2500

step-by-step explanation: