Prove: AC bisects DAB and BCD Identify the missing statement and reason in the proof.

Given rhombus ABCD with diagonal AC , it follows from the definition of a rhombus that AB BC CD AD. By the reflexive property of congruence, AC = AC . So, DAC = BAC by the ?

. Since corresponding parts of congruent triangles are congruent, DAC = ? and DCA = ?. So, by the definition of segment bisector AC bisects DAB and BCD .

With these 5 geometry questions! pls 1.)quadrilateral abcd is inscribed in this circle. what is the measure of ∠a ? enter your answer in the box.°2.)quadrilateral abcd is inscribed in a circle. what is the measure of angle a? enter your answer in the box. m∠a= 3.)quadrilateral abcd is inscribed in this circle. what is the measure of angle b? enter your answer in the box. m∠b= °4.)quadrilateral abcd is inscribed in this circle. what is the measure of angle a? enter your answer in the box.°5.) quadrilateral abcd is inscribed in this circle. what is the measure of angle c? enter your answer in the box.°