An object is dropped from a height of 25 meters at what velocity will it hot the ground

Given data

height (h) = 25 m ,

velocity (v) = ?

we know that,

                    v²-u² = 2as

                     initial velocity (u) = 0,

                                               a = g = 9.8 m/s ,

                 Now the equation becomes,

                                    v² = 2 × g × h

                                        = 2 × 9.8 × 25

                                    v² = 490.5

                                    v = √490.5

                                   v = 22.1 m/s

Therefore answer is C , i.e., 22 m/s

it is true

step-by-step explanation:

all the combinations add up i used   calculator

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)