The product of two natural numbers equals 2^3*3^4*5^2*7. What is the two numbers' greatest common factor?

The numbers also share one copy of 3, one copy of 5, and one copy of 7. 2940: 2×2×3 ... Consider two smaller numbers, 4 and 8, and their LCM. The number 4 ...

Step-by-step explanation

Step-by-step explanation:

You can't really tell what the two numbers are. They could be any combination of 2s for example

The first number could have no twos or 3 twos.

The second number could have the same values reversed. The givens don't confine us in any way. The only thing that is not a common factor in both numbers is 7 since there is only 1 of them.

Let us suppose the the first number is 2 * 2 * 3 * 3 *7 * 5

And the second number is 2 * 3 * 3 * 5

The highest common factor would be 2 * 3 * 3 * 5 = 90

However you could rearrange them like this

The first number = 2*3 * 7

The second number = 2 * 2 * 3*3*3 * 5 * 5

The highest common factor is 2*3 = 6

I don't think there is a unique answer to this.

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step-by-step explanation:

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