The total cost of trousers and three coats is 52 usd and the total cost 4 trousers and 4 coats is 72 usd what is the total cost of 6 trousers and coats?

Step-by-step explanation:

Let,

Cost of one trouser = $x

Cost of one coat = $y

In case 1

x + 3y = 52 (1)

In case 2

4x + 4y = 72

x + y = 18 (2)

On subtracting

x + 3y - (x + y) = 52 - 18

x + 3y - x - y = 52 - 18

2y = 34

y = 34/2

y = $17

From 2

x + y = 18

x + 17 = 18

x = 18 - 17

x = $1

Now,

Cost of 6 trouser and 6 coats

6x + 6y

6(x + y)

6(1 + 17)

6(18)

$108

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)

tube or goog would be a great resource to with that question