The sum of three consecutive odd integers is 129. find the integers

Step-by-step explanation:

Let the three consecutive integers be x, x + 2 and x + 4

So, the given condition is:

x + x + 2 + x + 4 = 129

3x + 6 = 129

Subtract 6 to both sides

3x = 129 - 6

3x = 123

Divide 3 to both sides

x = 123/3

x = 41

So, the integers are:

x = 41

x + 2 = 41 + 2 = 43

x + 4 = 41 + 4 = 45

Hope this helped!

Let the first number be = n

The difference of consecutive odd numbers is 2

So,the next two numbers are (n+2)(n+4)

Then,

→ (n) + (n+2) + (n+4) = 129

Remove brackets:

→ n + n + 2 + n + 4 = 129

→ 3n + 6 = 129

→ 3n = 129 – 6

→ 3n = 123

→

So, (n+2) = 41 + 2 = 43 , (n+4) = 41 + 4 = 45

» The three integers are 41, 43 and 45

$649.60

step-by-step explanation:

answer: the proof is mentioned below.

step-by-step explanation:

since, given:   lines bc = ef

prove:   lines ac > ef

          statements                                           reason

1. bc=ef                                           1. given

2. ac= ab+bc                                 2. because b is the point between the  

                                                            line segment ac

3.   ac > bc                                       3. because if a line segment is equal to

                                                          the sum of two line segments then it is

                                                          always greater then each of these

                                                          individual line segments

4. ac > ef                                         4. by equality property.