Why do you need to state restrictions on the variable when dividing rational expressions? A. To exclude values that will make the denominator of a rational expression equal 0.
B. To make sure that the rational expression always equals zero.
C. To exclude values that will make the numerator of a rational expression equal 0.
D. To make sure that the rational expression does not equal zero.

8496 cars

step-by-step explanation:

answer: none of these answers are correct only the second half is

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0