Find (fog)(x) when f(x)=x^2+6x+5 and g(x)=1/(x+1) A) (5x^2+16x+12)/(x^2+2x+1)
B) 1/(x^2+6x+6)
C) (6x^3+17x^2+16x+6)/(x^2+2x+1)
D) x+5

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

pretty sure 750 each month!

step-by-step explanation:

the formula of a slope:

we have the points (-2, 7) and (2, 3). substitute: